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对于已排序数组,二分法递归构造BST
代码:
1 TreeNode *buildBST(vector<int> &num, int i, int j) { 2 if (i > j) 3 return NULL; 4 5 int m = (i + j) /2; 6 TreeNode *node = new TreeNode(num[m]); 7 node->left = buildBST(num, i, m - 1); 8 node->right = buildBST(num, m + 1, j); 9 10 return node; 11 } 12 13 TreeNode *sortedArrayToBST(vector<int> &num) { 14 return buildBST(num, 0, num.size() - 1); 15 }
Leetcode#108 Convert Sorted Array to Binary Search Tree
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原文地址:http://www.cnblogs.com/boring09/p/4261537.html