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Leetcode#105 Construct Binary Tree from Preorder and Inorder Traversal

时间:2015-01-30 10:36:12      阅读:125      评论:0      收藏:0      [点我收藏+]

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原题地址

 

基本二叉树操作。

O[       ][              ]

[       ]O[              ]

 

代码:

 1 TreeNode *restore(vector<int> &preorder, vector<int> &inorder, int pp, int ip, int len) {
 2   if (len <= 0)
 3     return NULL;
 4 
 5   TreeNode *node = new TreeNode(preorder[pp]);
 6 
 7   if (len == 1)
 8     return node;
 9 
10   int leftLen = 0;
11   while (inorder[ip + leftLen] != preorder[pp])
12     leftLen++;
13   node->left = restore(preorder, inorder, pp + 1, ip, leftLen);
14   node->right = restore(preorder, inorder, pp + leftLen + 1, ip + leftLen + 1, len - leftLen - 1);
15 
16   return node;
17 }
18 
19 TreeNode *buildTree(vector<int> &preorder, vector<int> &inorder) {
20     return restore(preorder, inorder, 0, 0, preorder.size());
21 }

 

Leetcode#105 Construct Binary Tree from Preorder and Inorder Traversal

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原文地址:http://www.cnblogs.com/boring09/p/4261479.html

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