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二叉树基本操作
[ ]O[ ]
[ ][ ]O
代码:
1 TreeNode *restore(vector<int> &inorder, vector<int> &postorder, int ip, int pp, int len) { 2 if (len == 0) 3 return NULL; 4 5 TreeNode *node = new TreeNode(postorder[pp + len - 1]); 6 7 if (len == 1) 8 return node; 9 10 int leftLen = 0; 11 while (inorder[ip + leftLen] != postorder[pp + len - 1]) 12 leftLen++; 13 node->left = restore(inorder, postorder, ip, pp, leftLen); 14 node->right = restore(inorder, postorder, ip + leftLen + 1, pp + leftLen, len - leftLen - 1); 15 16 return node; 17 } 18 19 TreeNode *buildTree(vector<int> &inorder, vector<int> &postorder) { 20 return restore(inorder, postorder, 0, 0, inorder.size()); 21 }
Leetcode#106 Construct Binary Tree from Inorder and Postorder Traversal
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原文地址:http://www.cnblogs.com/boring09/p/4261502.html