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Kid want to learn math better.Now Kid know how to calculate the sum of 1 to n in a short time.But this time,he is given a much more difficult question——to calculate the sum of 1 to 10^n.Kid think for a long time——10^10 ms and then he solve the question successfully.
Do you know how to solve it ?
The first line is a integer t(1<=t<=10),indicate the number of case.
For each t,there is a integer n(the meaning of n is in the above),0<=n<=10^4.
For each case,just print the answer of the sum.
1 1
55
思路：其实这是由规律的n=1的时候是55，n=2的时候5050，n=3 500500,n=4 50005000。。。。一直下去
PS注意n=0事为1
#include <iostream> #include <cstdio> using namespace std; int main() { int t,n,i; scanf("%d",&t); while(t--) { scanf("%d",&n); if(n==0) { printf("1\n"); continue; } printf("5"); for(i=0; i<n-1; i++) { printf("0"); } printf("5"); for(i=0; i<n-1; i++) { printf("0"); } printf("\n"); } return 0; }
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原文地址：http://www.cnblogs.com/Wing0624/p/4264444.html
