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leetcode-Uniqe Paths

时间:2015-02-01 01:50:40      阅读:214      评论:0      收藏:0      [点我收藏+]

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题目

https://oj.leetcode.com/problems/unique-paths/
 
A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).
 
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).
 
How many possible unique paths are there?
 

思路

每个到达终点的方案需要向右m-1步,向下n-1步,一共m+n-2步;
从组合角度,可以理解为从m+n-2中选择m-1步向右走,剩下n-1步向下走。
 

代码

 1 class Solution:
 2     # @return an integer
 3     def uniquePaths(self, m, n):
 4         return int(self.combination(m+n-2, n-1))
 5     
 6     def combination(self, n, k):
 7         res = 1.0
 8         for i in range(1, k+1):
 9             res = res * (n - k + i) / i
10         return res
 
参考地址
1. https://oj.leetcode.com/discuss/9110/my-ac-solution-using-formula

leetcode-Uniqe Paths

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原文地址:http://www.cnblogs.com/ottll/p/4264997.html

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