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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 12771 Accepted Submission(s): 3290
3 aaa bbb ccc 2 aaabbbccc bbaacc
web 1: 1 2 3 total: 1
入门2,从给出的串中找出现的病毒串的序号,输出,防止多次统计,所以用vis记录是否出现过第i病毒。
#include <cstdio> #include <cstring> #include <algorithm> #include <queue> using namespace std ; struct node { int flag ; node *next[100] , *fail ; }; char str[11000] , s[210] ; queue <node*> que ; int vis[600] ; node *newnode() { node *p = new node ; p->flag = 0 ; p->fail = NULL ; int i ; for(i = 0 ; i < 100 ; i++) p->next[i] = NULL ; return p ; } void settree(char *s,node *rt,int temp) { int i , k , l = strlen(s) ; node *p = rt ; for(i = 0 ; i < l ; i++) { k = s[i] - 32 ; if( p->next[k] == NULL ) p->next[k] = newnode() ; p = p->next[k] ; } p->flag = temp ; } void setfail(node *rt) { int i , j , k ; node *p , *temp ; rt->fail = NULL; while( !que.empty() ) que.pop() ; que.push(rt) ; while( !que.empty() ) { p = que.front() ; que.pop() ; for(i = 0 ; i < 100 ; i++) { if( p->next[i] ) { temp = p->fail ; while( temp && !temp->next[i] ) temp = temp->fail ; p->next[i]->fail = temp ? temp->next[i] : rt ; que.push(p->next[i]) ; } else p->next[i] = p == rt ? rt : p->fail->next[i] ; } } } int query(char *str,node *rt) { int i , k , l = strlen(str) ; int flag = 0 ; node *p = rt , *temp ; for(i = 0 ; i < l ; i++) { k = str[i] - 32 ; p = p->next[k] ; temp = p ; while( temp && temp->flag ) { if( vis[ temp->flag ] ) break ; vis[ temp->flag ] = 1 ; flag = 1 ; temp = temp->fail ; } } return flag ; } int main() { int n , m , i , j , num ; node *rt ; while( scanf("%d", &n) != EOF) { rt = newnode() ; for(i = 1 ; i <= n ; i++) { scanf("%s", s) ; settree(s,rt,i) ; } setfail(rt) ; scanf("%d", &m) ; num = 0 ; for(i = 1 ; i <= m ; i++) { memset(vis,0,sizeof(vis)) ; scanf("%s", str) ; if( query(str,rt) ) { num++ ; printf("web %d:", i) ; for(j = 0 ; j < 600 ; j++) if( vis[j] ) printf(" %d", j) ; printf("\n") ; } } printf("total: %d\n", num) ; } return 0; }
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原文地址:http://blog.csdn.net/winddreams/article/details/43410235