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#title #Longest Substring Without Repeating Characters #description: #Given a string, #find the length of the longest substring without #repeating characters. For example, #the longest substring without repeating letters #for "abcabcbb" is "abc", which the length is 3. #For "bbbbb" the longest substring is "b", #with the length of 1. # one method:O(n) # dict.has_key need O(1) # substring forward a bit each step # class Solution: # # @return an integer # def lengthOfLongestSubstring(self, s): # substring = dict() # max_len = 1 # min_num = 0 # for i in range(len(s)): # if not substring.has_key(s[i]): # substring[s[i]] = i # if (i + 1 - min_num > max_len): # max_len = i + 1 - min_num # else: # if(substring[s[i]] + 1 > min_num): # min_num = substring[s[i]] + 1 # if(substring[s[i]] < min_num): # substring[s[i]] = min_num # if(i - substring[s[i]] > max_len): # max_len = i -substring[s[i]] # substring[s[i]] = i # print max_len,min_num,substring # return max_len #method two:need O(n) #add flag to fore_process #and note that print sentence class Solution: # @return an integer def lengthOfLongestSubstring(self, s): substring = dict() max_len = 1 min_num = 0 flag = dict() for i in range(len(s)): flag[s[i]] = 0 for i in range(len(s)): if flag[s[i]] == 0: flag[s[i]] = 1 substring[s[i]] = i if (i + 1 - min_num > max_len): max_len = i + 1 - min_num else: if(substring[s[i]] + 1 > min_num): min_num = substring[s[i]] + 1 if(substring[s[i]] < min_num): substring[s[i]] = min_num if(i - substring[s[i]] + 1 > max_len): max_len = i + 1 - substring[s[i]] substring[s[i]] = i # print max_len,min_num,substring if len(s) == 0: max_len = 0 return max_len if __name__ == ‘__main__‘: s = Solution() substring = ‘abcabcbb‘ substring = ‘bbbbb‘ substring = ‘abcabbcaa‘ substring = ‘ynqogshxhchhpqhjrwwtdm‘ substring = ‘bhhoejpnsoqioadvynqrbo‘ # substring = ‘‘ # substring = ‘tmmzuxt‘ print s.lengthOfLongestSubstring(substring)
Longest Substring Without Repeating Characters
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原文地址:http://www.cnblogs.com/xieweichong/p/4269640.html