解题思路:
求相同的前缀和后缀。开一个数组保存到i位置,模式串有多少个字符和文本串匹配即可。
#include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <algorithm> #include <cmath> #include <vector> #include <queue> #include <stack> #define LL long long #define FOR(i,x,y) for(int i=x;i<=y;i++) using namespace std; const int maxn = 100000 + 10; char s[maxn], t[maxn]; int c[maxn]; int next[maxn]; void get_next() { int m = strlen(s); next[0] = 0; next[1] = 0; for(int i=1;i<m;i++) { int j = next[i]; while(j && s[i] != s[j]) j = next[j]; next[i+1] = (s[i] == s[j]) ? j + 1 : 0; } } int KMP() { int n = strlen(t), m = strlen(s); get_next(); int j = 0; for(int i=0;i<n;i++) { while(j && s[j] != t[i]) j = next[j]; if(s[j] == t[i]) j++; c[i] = j; } } int main() { while(scanf("%s", s)!=EOF) { scanf("%s", t); KMP(); int n = strlen(t); if(c[n-1] == 0) printf("0\n"); else { for(int i=0;i<c[n-1];i++) printf("%c", s[i]); printf(" %d\n", c[n-1]); } } return 0; }
HDU 2594 Simpsons’ Hidden Talents(KMP)
原文地址:http://blog.csdn.net/moguxiaozhe/article/details/43447575