PAT1065. A+B and C (64bit)

标签：

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

思路：此题有一点需要注意，以后不要在if里面进行计算因为可能有问题 ,需要开始个临时变量。

 1 #include<cstdio>
 2 int main(int argc, char *argv[])
 3 {
 4     int T;
 5     long long a;
 6     long long b;
 7     long long c;
 8     scanf("%d",&T);
 9     for(int i=1;i<=T;i++)
10     {
11         scanf("%lld%lld%lld",&a,&b,&c);
12         bool flag;
13         long long temp=a+b;         //????????????? 
14         if(a>0&&b>0&&temp<0)
15             flag=true;
16         else if(a<0&&b<0&&temp>=0)  //?????
17             flag=false;
18         else if(temp>c)
19             flag=true;
20         else 
21             flag=false;
22         if(flag)
23           printf("Case #%d: true\n",i);
24         else 
25           printf("Case #%d: false\n",i);
26     }
27     return 0;
28 }

View Code

PAT1065. A+B and C (64bit)

标签：

原文地址：http://www.cnblogs.com/GoFly/p/4270890.html