candy

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There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

• Each child must have at least one candy.
• Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

解题思路:用了比较麻烦的方法，遍历两遍数组，第一遍对于确保右边比左边的人拿到的糖果符合条件;第二遍遍历来修正左边对于右边的情况;

#include<iostream>
#include<vector>
#include<numeric>
using namespace std;

int candy(vector<int> &ratings) {

	int ChildrenNum = ratings.size();
	vector<int>CandyVector(ChildrenNum, 1);
	for (int i = 0; i < ChildrenNum-1;++i){
		if (ratings[i] < ratings[i + 1])
			CandyVector[i + 1] = CandyVector[i] + 1;
	}
	for (int i = ChildrenNum-1; i >0; --i){
		if (ratings[i] < ratings[i - 1]&&CandyVector[i]>=CandyVector[i-1])
			CandyVector[i - 1] = CandyVector[i] + 1;
	}
	return accumulate(CandyVector.begin(), CandyVector.end(), 0);
}

candy

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原文地址：http://blog.csdn.net/li_chihang/article/details/43485903