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Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.
Input Specification:
Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).
Output Specification:
For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.
12345
one five
思路：一定要注意数值的取值范围，10^100可能不是longlong 就能解决的问题
1 #include<cstdio> 2 #include<cstring> 3 char data[11][10]= 4 { 5 "zero", 6 "one", 7 "two", 8 "three", 9 "four", 10 "five", 11 "six", 12 "seven", 13 "eight", 14 "nine" 15 }; 16 char str[200]; 17 int main(int argc, char *argv[]) 18 { 19 scanf("%s",str); 20 int sum=0; 21 for(int i=0;str[i]!=‘\0‘;i++) 22 { 23 sum+=str[i]-‘0‘; 24 } 25 sprintf(str,"%d",sum); 26 for(int i=0;i<strlen(str);i++) 27 { 28 int index=str[i]-‘0‘; 29 if(i==strlen(str)-1) 30 printf("%s\n",data[index]); 31 else 32 printf("%s ",data[index]); 33 } 34 return 0; 35 }
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原文地址：http://www.cnblogs.com/GoFly/p/4272551.html
