标签:
Given an array with positive and negative integers. Re-range it to interleaving with positive and negative integers.You are not necessary to keep the original order or positive integers or negative integers.
Given [-1, -2, -3, 4, 5, 6], after re-range, it will be [-1, 5, -2, 4, -3, 6] or any other legal answer.
Do it in-place and without extra memory.
看了网上的一些解法,是很巧妙,但是编程起来感觉没自己的这个更清晰些!分享下咯
class Solution { /** * @param A: An integer array. * @return an integer array */ public int[] rerange(int[] A) { if(A==null || A.length<=1) return A; int s = 0; int p1 = -1; int p2 = -1; for(int i=0;i<A.length;i++){ if(p1 == -1 && A[i] > 0) p1 = i; if(p1 == -1 && A[i] < 0) p2 = i; s += A[i] > 0?1:-1; } if(s<0) p1 = p2; int tmp = A[0]; A[0] = A[p1]; A[p1] = tmp; for(int i=1;i<A.length;i++){ int j=i; while(j<A.length && A[j] * A[i-1]>0) j++; if(j>i && j<A.length){ tmp = A[i]; A[i] = A[j]; A[j] = tmp; } } return A; } }
[leetcode]Interleaving Positive and Negative Numbers
标签:
原文地址:http://blog.csdn.net/wankunde/article/details/43525947