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杭电ACM 蜗牛出井

时间:2015-02-06 21:51:59      阅读:272      评论:0      收藏:0      [点我收藏+]

标签:c++   cpp   大一练习   计算机   

Problem Description

A snail is at the bottom of a 6-foot well and wants to climb to the top. The snail can climb 3 feet while the sun is up, but slides down 1 foot at night while sleeping. The snail has a fatigue factor of 10%, which means that on each successive day the snail climbs 10% * 3 = 0.3 feet less than it did the previous day. (The distance lost to fatigue is always 10% of the first day‘s climbing distance.) On what day does the snail leave the well, i.e., what is the first day during which the snail‘s height exceeds 6 feet? (A day consists of a period of sunlight followed by a period of darkness.) As you can see from the following table, the snail leaves the well during the third day.

Day Initial Height Distance Climbed Height After Climbing Height After Sliding
1 0 3 3 2
2 2 2.7 4.7 3.7
3 3.7 2.4 6.1 -

Your job is to solve this problem in general. Depending on the parameters of the problem, the snail will eventually either leave the well or slide back to the bottom of the well. (In other words, the snail‘s height will exceed the height of the well or become negative.) You must find out which happens first and on what day.

Input

The input file contains one or more test cases, each on a line by itself. Each line contains four integers H, U, D, and F, separated by a single space. If H = 0 it signals the end of the input; otherwise, all four numbers will be between 1 and 100, inclusive. H is the height of the well in feet, U is the distance in feet that the snail can climb during the day, D is the distance in feet that the snail slides down during the night, and F is the fatigue factor expressed as a percentage. The snail never climbs a negative distance. If the fatigue factor drops the snail‘s climbing distance below zero, the snail does not climb at all that day. Regardless of how far the snail climbed, it always slides D feet at night.

Output

For each test case, output a line indicating whether the snail succeeded (left the well) or failed (slid back to the bottom) and on what day. Format the output exactly as shown in the example.

Sample Input

6 3 1 10
10 2 1 50
50 5 3 14
50 6 4 1
50 6 3 1
1 1 1 1
0 0 0 0

Sample Output

success on day 3
failure on day 4
failure on day 7
failure on day 68
success on day 20
failure on day 2
/*
*Copyright (c)2014,烟台大学计算机与控制工程学院
*All rights reserved.
*文件名称:test.cpp
*作    者:冷基栋
*完成日期:2015年2月6日
*版 本 号:v1.0
*问题描述:蜗牛出井
*程序输入:四个整数,分别代表井的高度H,白天爬行路程U,晚上下滑路程D,体力消耗F
*程序输出:蜗牛能否爬出,第几天
*/

#include  <iostream>
using namespace std;
int main( )
{
    double h,u,d,f,t,s;
    while (cin>>h>>u>>d>>f&&(h||u||d||f))
    {
        int day=0,flog=1;
        s=0;
        t=u*f*0.01;
        while(s<=h)
        {
            day++;
            s+=u;
            if(s>h)
                break;
               s-=d;
            if(s<0)
            {
                flog=0;
                break;
            }
            u-=t;
        }
        if(flog==1)
            cout<<"success on day "<<day<<endl;
        else
            cout<<"failure on day "<<day<<endl;
    }
    return 0;
}

运行结果:

技术分享

知识点总结:

读懂题意很重要 是少走了百分之十

学习心得:

好好学习 天天向上





杭电ACM 蜗牛出井

标签:c++   cpp   大一练习   计算机   

原文地址:http://blog.csdn.net/ljd939952281/article/details/43572653

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