标签:c style class blog code java
Given a linked list, return the node where the cycle begins. If there is no
cycle, return null
.
Follow up:
Can you solve it without using extra space?
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *detectCycle(ListNode *head) { if(head==NULL || head->next==NULL) return NULL; //check if cycle exist ListNode* p1=head; ListNode* p2=head; while(true) { p1=p1->next; p2=p2->next; if(p2==NULL || p2->next==NULL) return NULL; p2=p2->next; if(p1==p2) break; } p2=head; while(p1!=p2) { p1=p1->next; p2=p2->next; } return p1; } };
Linked List Cycle II,布布扣,bubuko.com
标签:c style class blog code java
原文地址:http://www.cnblogs.com/erictanghu/p/3759713.html