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题目描述：Regular Expression Matching
Implement regular expression matching with support for ‘.‘ and ‘*‘
‘.‘ Matches any single character.
‘*‘ Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s, const char *p)
Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true
代码如下：
class Solution { public: bool isMatch(const char *s, const char *p) { if(*p == ‘\0‘) return *s == ‘\0‘; //如果下一个字符不是*，那么就需要匹配当前的字符！ if(*(p + 1) != ‘*‘){ //下一个字符相等，或者有一个是‘.‘，则匹配成功 if(*p == *s || (*p == ‘.‘ && *s != ‘\0‘)) return isMatch(s + 1, p + 1); else return false; } //下一个字符是*，则当前字符可以为0个或多个！ else{ while(*p == *s || (*p == ‘.‘ && *s != ‘\0‘)){ if(isMatch(s, p + 2)) return true; s++; } return isMatch(s, p + 2); } } };
LeetCode 010 Regular Expression Matching
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原文地址：http://www.cnblogs.com/510602159-Yano/p/4278702.html
