标签：
Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
class Solution { public: int compareVersion(string version1, string version2) { int i=0,j=0; while(i<version1.length()||j<version2.length()) { int num1=0,num2=0; while(i<version1.length()) { if(version1[i]==‘.‘) { i++; break; } else num1=num1*10+(version1[i++]-‘0‘); } while(j<version2.length()) { if(version2[j]==‘.‘) { j++; break; } else num2=num2*10+(version2[j++]-‘0‘); } if(num1<num2)return -1; if(num1>num2)return 1; } return 0; } };
leetcode[165]Compare Version Numbers
标签：
原文地址：http://www.cnblogs.com/Vae98Scilence/p/4280682.html
