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Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next()
will return the next smallest number in the BST.
Note: next()
and hasNext()
should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class BSTIterator { private: stack<TreeNode *> sta; public: void leftOrder(TreeNode *root) { if(root==NULL)return; TreeNode *tmp=root; while(tmp) { sta.push(tmp); if(tmp->left) { tmp=tmp->left; } else break; } return; } BSTIterator(TreeNode *root) { leftOrder(root); } /** @return whether we have a next smallest number */ bool hasNext() { return !sta.empty(); } /** @return the next smallest number */ int next() { TreeNode *top=sta.top(); sta.pop(); if(top->right)leftOrder(top->right); return top->val; } }; /** * Your BSTIterator will be called like this: * BSTIterator i = BSTIterator(root); * while (i.hasNext()) cout << i.next(); */
leetcode[173]Binary Search Tree Iterator
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原文地址:http://www.cnblogs.com/Vae98Scilence/p/4280657.html