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Given n, generate all structurally unique BST‘s (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST‘s shown below.
1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void creatTree(vector<TreeNode *> &res,int start, int end) { if(start>end) { res.push_back(NULL); return; } for(int k=start;k<=end;k++) { vector<TreeNode *> left; vector<TreeNode *> right; creatTree(left,start,k-1); creatTree(right,k+1,end); for(int i=0;i<left.size();i++) { for(int j=0;j<right.size();j++) { TreeNode *root=new TreeNode(k); root->left=left[i]; root->right=right[j]; res.push_back(root); } } } return; } vector<TreeNode *> generateTrees(int n) { vector<TreeNode *> res; creatTree(res,1,n); return res; } };
leetcode[95]Unique Binary Search Trees II
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原文地址:http://www.cnblogs.com/Vae98Scilence/p/4281378.html