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Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5
, return 1->2->5
.
Given 1->1->1->2->3
, return 2->3
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *deleteDuplicates(ListNode *head) { if(head==NULL||head->next==NULL)return head; ListNode *tmp=head->next; ListNode *res=new ListNode(0); res->next=head; ListNode *p=res->next; ListNode *pre=res; int value=head->val; while(tmp!=NULL) { if(p->val!=tmp->val&&value!=tmp->val) { p->next=tmp; pre=p; p=p->next; value=tmp->val; } else { p=pre; } tmp=tmp->next; } p->next=NULL; return res->next; } };
leetcode[82]Remove Duplicates from Sorted List II
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原文地址:http://www.cnblogs.com/Vae98Scilence/p/4281419.html