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Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 mightbecome 4 5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
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int findMin(vector<int> &num) {
int size = num.size();
for (int i = 0; i < size - 1; i++)
if (num[i]>num[i + 1])
return num[i + 1];
return num[0];//num升序排列,没有转置
}
153.Find Minimum in Rotated Sorted Array
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原文地址:http://blog.csdn.net/hgqqtql/article/details/43707415