题目：http://poj.org/problem?id=1056
题意：判断是否有串是其他串的前缀
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71 |
#include<algorithm>#include<stdio.h>#include<iostream>#include<set>#include<map>#include<queue>#include<stack>#include<string.h>using
namespace std;struct
Node{ int
cnt;Node * next[50];}e[111111];int
len=0;Node * newnode(){ memset(&e[len],0,sizeof(e[len])); return
&e[len++];}void
Insert(char
*s,Node *root){ int
len=strlen(s); for(int
i=0;i<len;i++){ int
cc=s[i]-‘0‘; if(!root->next[cc]){ root->next[cc]=newnode(); } root->cnt++; root=root->next[cc]; } root->cnt++;}int
Find(char
*s,Node *root){ int
len=strlen(s); for(int
i=0;i<len;i++){ int
cc=s[i]-‘0‘; root=root->next[cc]; } if(root->cnt>1) return
1; else return
0;}char
str[1005][1005];int
main(){ int
i=-1;int
ret=1;int
flag=0;Node *root=newnode(); while(scanf("%s",&str[++i])!=EOF){ Insert(str[i],root); if(strcmp(str[i],"9")==0){ for(int
j=0;j<i;j++){ if(Find(str[j],root)){ flag=1; printf("Set %d is not immediately decodable\n",ret++);break; } } if(flag==0){ printf("Set %d is immediately decodable\n",ret++); } i=-1;len=0;flag=0;root=newnode(); } } return
0;} |
Trie树 POJ1056 IMMEDIATE DECODABILITY,布布扣,bubuko.com
Trie树 POJ1056 IMMEDIATE DECODABILITY
原文地址：http://www.cnblogs.com/yigexigua/p/3761300.html
