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1 #include<iostream> 2 #include<queue> 3 #include<cstdio> 4 #include<cstring> 5 #include<cmath> 6 #include<algorithm> 7 using namespace std; 8 int map[15][15]; 9 int main(){ 10 int P,T,G1,G2,G3,GJ; 11 while(cin>>P>>T>>G1>>G2>>G3>>GJ){ 12 if(abs(G1-G2)<=T){ 13 printf("%.1lf\n",1.0*(G1+G2)/2); 14 } 15 else{ 16 int m1=abs(G1-G3); 17 int m2=abs(G3-G2); 18 if(m1<=T&&m2<=T){ 19 int max=G1>G2?G1:G2; 20 max=max>G3?max:G3; 21 printf("%.1lf\n",max*1.0); 22 } 23 else{ 24 if(m1<=T||m2<=T){ 25 if(m1>m2){ 26 printf("%.1lf\n",(G3+G2)*1.0/2); 27 } 28 else{ 29 printf("%.1lf\n",(G3+G1)*1.0/2); 30 } 31 } 32 else{ 33 printf("%.1lf\n",GJ*1.0); 34 } 35 } 36 } 37 } 38 return 0; 39 }
时间限制:1 秒
内存限制:32 兆
特殊判题:否
提交:16128
解决:4162
Grading hundreds of thousands of Graduate Entrance Exams is a hard work. It is even harder to design a process to make the results as fair as possible. One way is to assign each exam problem to 3 independent experts. If they do not agree to each other, a judge is invited to make the final decision. Now you are asked to write a program to help this process.
For each problem, there is a full-mark P and a tolerance T(<P) given. The grading rules are:
• A problem will first be assigned to 2 experts, to obtain G1 and G2. If the difference is within the tolerance, that is, if |G1 - G2| ≤ T, this problem‘s grade will be the average of G1 and G2.
• If the difference exceeds T, the 3rd expert will give G3.
• If G3 is within the tolerance with either G1 or G2, but NOT both, then this problem‘s grade will be the average of G3 and the closest grade.
• If G3 is within the tolerance with both G1 and G2, then this problem‘s grade will be the maximum of the three grades.
• If G3 is within the tolerance with neither G1 nor G2, a judge will give the final grade GJ.
Each input file may contain more than one test case.
Each case occupies a line containing six positive integers: P, T, G1, G2, G3, and GJ, as described in the problem. It is guaranteed that all the grades are valid, that is, in the interval [0, P].
For each test case you should output the final grade of the problem in a line. The answer must be accurate to 1 decimal place.
20 2 15 13 10 18
14.0
九度oj 1002 Grading 2011年浙江大学计算机及软件工程研究生机试真题
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原文地址:http://www.cnblogs.com/Deribs4/p/4288875.html