PAT1083. List Grades

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Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade‘s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student‘s name and ID, separated by one space. If there is no student‘s grade in that interval, output "NONE" instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

思路：本题无思路。

 1 #include <iostream>
 2 #include <cstdio>
 3 #include <algorithm>
 4 using namespace std;
 5 #define MAX 100010
 6 struct Record
 7 {
 8     char name[12];
 9     char ID[12];
10     int grade;
11 }Record[MAX];
12 bool cmp(struct Record A,struct Record B)
13 {
14     return A.grade>B.grade;
15 }
16 int main(int argc, char *argv[])
17 {
18     int N;
19     scanf("%d",&N);
20     for(int i=0;i<N;i++)
21     {
22         scanf("%s %s %d",Record[i].name,Record[i].ID,&Record[i].grade);
23     }
24     sort(Record,Record+N,cmp);
25     int grade1,grade2;
26     scanf("%d%d",&grade1,&grade2);
27     bool flag=false;
28     for(int i=0;i<N;i++)
29     {
30         if(Record[i].grade>=grade1&&Record[i].grade<=grade2)
31         {
32             flag=true;
33             printf("%s %s\n",Record[i].name,Record[i].ID);
34         }
35     }
36     if(!flag)
37        printf("NONE\n");
38     return 0;
39 }

View Code

PAT1083. List Grades

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原文地址：http://www.cnblogs.com/GoFly/p/4290816.html