0
1
2
3
4
5

no
no
yes
no
no
no

#include<iostream>
using namespace std;
int diaoyong(int n)
{
	if(n>=2)
		return diaoyong(n-1)+diaoyong(n-2);
	if(n==1)
		return 11;
	if(n==0)
		return 7;
}
int main()
{
	int n;     
	while(scanf("%d",&n)!=EOF)       //f[4]=3 + 2=2+1 +1+0 =1+0+1+1+0=33+14=47
	{
        if(diaoyong(n)%3==0)
			cout<<"yes"<<endl;
		else
			cout<<"no"<<endl;
	}
	return 0;
}

#include<iostream>
using namespace std;
int main()
{
    int n;
    while(scanf("%d",&n)!=EOF)
    {
       if(n%8==2 ||n%8==6)
           cout<<"yes"<<endl;
       else
           cout<<"no"<<endl;
    }
    return 0;
}