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注意要记录每一个数的出现次数,然后对数组排序,去重,再按题目的意思计算,注意用int会溢出
/*************************************************************************
> File Name: bc30-a.cpp
> Author: ALex
> Mail: zchao1995@gmail.com
> Created Time: 2015年02月14日 星期六 18时53分26秒
************************************************************************/
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <vector>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const double pi = acos(-1);
const int inf = 0x3f3f3f3f;
const double eps = 1e-15;
typedef long long LL;
typedef pair <int, int> PLL;
const LL mod = 2147483647;
LL arr[111];
map <LL, int> re;
int main ()
{
int n;
int icase = 1;
while (~scanf("%d", &n))
{
re.clear();
for (int i = 1; i <= n; ++i)
{
scanf("%I64d", &arr[i]);
re[arr[i]]++;
}
printf("Case #%d: ", icase++);
sort (arr + 1, arr + 1 + n);
n = unique (arr + 1, arr + 1 + n) - arr - 1;
if (n == 1)
{
printf("-1\n");
continue;
}
int ans = 0;
for (int i = 1; i <= n; ++i)
{
if (i == 1)
{
if ((arr[n] + arr[1]) % mod == arr[2])
{
ans += re[arr[1]];
}
}
else if (i == n)
{
if ((arr[n - 1] + arr[n]) % mod == arr[1])
{
ans += re[arr[n]];
}
}
else
{
if ((arr[i - 1] + arr[i]) % mod == arr[i + 1])
{
ans += re[arr[i]];
}
}
}
printf("%d\n", ans);
}
return 0;
}
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原文地址:http://blog.csdn.net/guard_mine/article/details/43820387