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直接枚举0~X就可以了。。。我开始竟然往扩展欧几里德定理想了,呃呃---
#include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> using namespace std; char st[20]; int main() { //freopen("t.txt", "r", stdin); gets(st); int ans = 0; int pos = 0; for (int i = 0; i < 10; i++) if (st[i] == ‘?‘) pos = 10 - i; else if (st[i] == ‘X‘) ans += 10 * (10 - i); else ans += (st[i] - ‘0‘) * (10 - i); for (int i = 0; i <= 9; i++) if ((ans + i * pos) % 11 == 0) { printf("%d\n", i); return 0; } if ((ans + 10 * pos) % 11 == 0 && pos == 1) { printf("X\n"); return 0; } printf("-1\n"); return 0; }
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原文地址:http://www.cnblogs.com/jie-dcai/p/4292302.html