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poj 2105 IP Address

时间:2015-02-16 14:11:13      阅读:164      评论:0      收藏:0      [点我收藏+]

标签:

IP Address
Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions: 18951   Accepted: 10939

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of ‘1s‘ and ‘0s‘ (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are: 
2
7
   2
6
  2
5
  2
4
  2
3
   2
2
  2
1
  2
0
 

128 64 32 16 8 4 2 1

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

4
00000000000000000000000000000000 
00000011100000001111111111111111 
11001011100001001110010110000000 
01010000000100000000000000000001 

Sample Output

0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1

Source

 
分析:
进制转换
 1 #include <cstdio>
 2 #include<algorithm>
 3 #include<iostream>
 4 #include<string>
 5 #include<cstring>
 6 #include<vector>
 7 using namespace std;
 8 int b[8]={128,64,32,16,8,4,2,1};
 9 int main(){
10     int n;
11     string s;
12     while(cin>>n){
13         while(n--){
14             cin>>s;
15             int i,j,k=0;
16             for(i=0;i<=31;){
17                 int sum=0;
18                 j=0;
19                 while(j<8){
20                     if(s[i]==1)
21                     sum+=b[i%8];
22                     i++;
23                     j++;
24                 }
25                 cout<<sum;
26                 if(k<3){
27                     cout<<.;
28                 }
29                 else{
30                     cout<<endl;
31                 }
32                 k++;
33             }
34         }
35     }
36     return 0;
37 } 

 

poj 2105 IP Address

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原文地址:http://www.cnblogs.com/Deribs4/p/4294036.html

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