码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode Remove Duplicates from Sorted Array

时间:2015-02-17 21:05:58      阅读:168      评论:0      收藏:0      [点我收藏+]

标签:

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array A = [1,1,2],

Your function should return length = 2, and A is now [1,2].

题意:给已经排好序的数组去重。

思路:每次拿一个数去依次比较,如果不一样的话就能录入新数组,不然就继续找。

class Solution {
public:
    int removeDuplicates(int A[], int n) {
        if (n == 0) return 0;

        int len = 0;
        int tmp = A[0];
        for (int i = 0; i < n; i++) {
            if (A[i] != tmp) {
                A[len++] = tmp;
                tmp = A[i];
            }
        }
        A[len++] = tmp;

        return len;
    }
};



LeetCode Remove Duplicates from Sorted Array

标签:

原文地址:http://blog.csdn.net/u011345136/article/details/43867839

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!