标签:
8 1300 48 2 1 7 0
2504 1000
#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
__int64 A,B;
int m,i,a[10000];
while(scanf("%d",&m))
{
int k=0;
int sum=0;
if(m==0)
break;
scanf("%I64d%I64d",&A,&B);
sum=A+B;
a[k++]=sum%m;//8 2 0001
sum=sum/m; //2 2 01
while(sum)
{
a[k++]=sum%m;
sum=sum/m;
}
for(i=k-1;i>=0;i--)
cout<<a[i];
cout<<endl;
}
return 0;
}标签:
原文地址:http://blog.csdn.net/zuguodexiaoguoabc/article/details/43882289