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传送门:http://poj.org/problem?id=1094
Description
Input
Output
Sample Input
4 6 A<B A<C B<C C<D B<D A<B 3 2 A<B B<A 26 1 A<Z 0 0
Sample Output
Sorted sequence determined after 4 relations: ABCD. Inconsistency found after 2 relations. Sorted sequence cannot be determined.
思路:topo排序:1:判断是否有环;2:判断答案是否唯一;3:全部读入,序列不确定;
代码:
#include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<string> #include<queue> #include<stack> #include<map> #define INF 0x3f3f3f3f #define mem(a,b) memset(a,b,sizeof(a)) using namespace std; typedef long long LL; const int N=1002; vector<int> E[30],ans; int indegree[30]; int topo(int n) { int tmp[30]; for(int i=0;i<30;i++) tmp[i]=indegree[i]; ans.clear(); int cnt=0,cur,flag=1; for(int i=0;i<n;i++) { cnt=0; for(int j=0;j<n;j++) { if(tmp[j]==0) { cnt++; cur=j; } } if(cnt==0) return 0; if(cnt>1) flag=-1; //unsure ans.push_back(cur); tmp[cur]=-1; for(int j=0;j<E[cur].size();j++) { int v=E[cur][j]; tmp[v]--; } } return flag; } int main() { int n,m; while(scanf("%d%d",&n,&m)==2){ if(n==0&&m==0) break; char str[10]; mem(indegree,0); for(int i=0;i<n;i++) E[i].clear(); int ok=0; for(int i=1;i<=m;i++){ scanf("%s",str); E[str[0]-'A'].push_back(str[2]-'A'); indegree[str[2]-'A']++; int res=topo(n); if(ok) continue; if(res==0) { printf("Inconsistency found after %d relations.\n",i); ok=1; } if(res==1) { printf("Sorted sequence determined after %d relations: ",i); for(int j=0;j<ans.size();j++) printf("%c",ans[j]+'A'); printf(".\n"); ok=1; } } if(!ok) printf("Sorted sequence cannot be determined.\n"); } return 0; }
poj 1094 Sorting It All Out[ topo]
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原文地址:http://blog.csdn.net/code_or_code/article/details/43884089