找最小路径是否有负环就好
#include<iostream>
#include<cstring>
using namespace std;
struct node
{
int s,e,t;
};
node path[5201];
bool bellmanford(int s,int sw,int v,int e)
{
bool flag;
int weight[501],i;
memset(weight,60,sizeof(weight));
weight[s]=sw;
while(v--)
{
flag=1;
for(i=1;i<=e;i++)
{
if(weight[path[i].e]>weight[path[i].s]+path[i].t)
{
flag=0;
weight[path[i].e]=weight[path[i].s]+path[i].t;
}
}
if(flag)
return 0;
}
return 1;
}
int main()
{
int i,f,n,m,w;
scanf("%d",&f);
while(f--)
{
scanf("%d%d%d",&n,&m,&w);
for(i=1;i<=2*m;i++)
{
scanf("%d%d%d",&path[i].s,&path[i].e,&path[i].t);
i++;
path[i].s=path[i-1].e;
path[i].e=path[i-1].s;
path[i].t=path[i-1].t;
}
for(;i<=2*m+w;i++)
{
scanf("%d%d%d",&path[i].s,&path[i].e,&path[i].t);
path[i].t=-path[i].t;
}
if(bellmanford(1,0,n,i-1))
{
printf("YES\n");
}
else
{
printf("NO\n");
}
}
}
原文地址:http://blog.csdn.net/stl112514/article/details/27111069