标签:
splay可以用于维护序列,比如noi的维修序列,比如这道
发现当时splay没写总结,也没题解
然后重新写splay竟然耗了一个晚上
结果是因为max【0】没有附最小值!!血一样的教训
最后祭出inline大法才过,我的splay真的慢到吐血
{$inline on} {$M 1000000000,0,maxlongint} const //mm=maxlongint>>2; maxn=60000; var size,left,right,mark,fa,value,max:array[0..maxn]of longint; rev:array[0..maxn]of boolean; root,i,j,k,l,n,m,tot,x:longint; function new:longint;inline; begin inc(tot); exit(tot); end; function mmax(x,y:longint):longint;inline; begin if x<y then exit(y); exit(x) end; procedure swap(var x,y:longint);inline; var i:longint; begin i:=x; x:=y; y:=i; end; procedure pushdown(x:longint);inline; begin if x=0 then exit; if rev[x] then begin swap(left[x],right[x]); rev[left[x]]:=rev[left[x]] xor true; rev[right[x]]:=rev[right[x]] xor true; rev[x]:=false; end; if mark[x]<>0 then begin value[x]:=value[x]+mark[x]; max[x]:=max[x]+mark[x]; inc(mark[left[x]],mark[x]); inc(mark[right[x]],mark[x]); mark[x]:=0; end; end; procedure update(x:longint);inline; begin pushdown(x); pushdown(left[x]); pushdown(right[x]); size[x]:=size[left[x]]+size[right[x]]+1; max[x]:=mmax(value[x],mmax(max[left[x]],max[right[x]])); end; procedure lt(x:longint);inline; var u,k:longint; flag:boolean; begin pushdown(x); pushdown(right[x]); k:=right[x]; u:=fa[x]; if left[u]=x then flag:=true else flag:=false; right[x]:=left[k]; fa[right[x]]:=x; left[k]:=x; fa[x]:=k; update(x); update(k); fa[k]:=u; if flag then left[u]:=k else right[u]:=k; end; procedure rt(x:longint);inline; var u,k:longint; flag:boolean; begin pushdown(x); pushdown(left[x]); k:=left[x]; u:=fa[x]; if left[u]=x then flag:=true else flag:=false; left[x]:=right[k]; fa[left[x]]:=x; right[k]:=x; fa[x]:=k; update(x); update(k); fa[k]:=u; if flag then left[u]:=k else right[u]:=k; end; procedure splay(x,u:longint);inline; begin while fa[x]<>u do begin if fa[fa[x]]=u then begin if left[fa[x]]=x then rt(fa[x]) else lt(fa[x]); exit; end; if left[fa[x]]=x then begin if left[fa[fa[x]]]=fa[x] then rt(fa[fa[x]]); rt(fa[x]); end else begin if right[fa[fa[x]]]=fa[x] then lt(fa[fa[x]]); lt(fa[x]); end; end; end; function find(x,y:longint):longint;inline; begin pushdown(x); if size[left[x]]=y-1 then exit(x); if y<=size[left[x]] then exit(find(left[x],y)) else exit(find(right[x],y-1-size[left[x]])); end; function change(j,k:longint):longint;inline; var now:longint; begin now:=find(root,j); splay(now,0); root:=now; now:=find(root,k+2); splay(now,root); exit(now); end; function build(l,r:longint):longint;inline; var mid,x:longint; begin mid:=(l+r)>>1; x:=new; value[x]:=0; size[x]:=r-l+1; rev[x]:=false; mark[x]:=0; left[x]:=0; right[x]:=0; if l=r then begin if (l=0) or (l=n+1) then value[x]:=-maxlongint>>1; max[x]:=value[x]; exit(x); end; if l<mid then begin left[x]:=build(l,mid-1); fa[left[x]]:=x; end; if mid<r then begin right[x]:=build(mid+1,r); fa[right[x]]:=x; end; update(x); exit(x); end; begin readln(n,m); max[0]:=-maxlongint; root:=build(0,n+1); while m>0 do begin dec(m); read(j); if j=1 then begin readln(j,k,l); x:=change(j,k); inc(mark[left[x]],l); update(x); update(root); end else if j=2 then begin readln(j,k); x:=change(j,k); rev[left[x]]:=rev[left[x]] xor true; update(x); update(root); end else begin readln(j,k); x:=change(j,k); writeln(max[left[x]]); end; end; end.
splay还可以当普通的平衡树做?就是把旋转改为旋转为根?再找到题写吧。
标签:
原文地址:http://www.cnblogs.com/Macaulish/p/4299044.html