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Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
#include<iostream> #include<vector> using namespace std; //穷举 int threeSumClosest(vector<int> &num, int target) { int ClosestTarget = INT_MAX; int ClosestLength = INT_MAX; for (int first = 0; first !=num.size();++first){ for (int second = first + 1; second < num.size();++second){ for (int third = second + 1; third < num.size();++third){ int sum = num[first] + num[second] + num[third]; int temp = abs(sum-target); if (temp == 0) return target; if (temp<ClosestLength){ ClosestLength = temp; ClosestTarget = sum; } } } } return ClosestTarget; }
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原文地址:http://blog.csdn.net/li_chihang/article/details/44034057