标签:
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode p1 = l1; ListNode p2 = l2; ListNode h = new ListNode(0);//创建一个头结点 ListNode r = h;//设立一个尾指针 int carry = 0;//进位 int sum = 0;//对应位及进位相加之和 while(p1!=null||p2!=null) { if(p1!=null&&p2!=null){ sum = p1.val+p2.val+carry; p1 = p1.next; p2 = p2.next; } else { if(p1==null) { sum = p2.val+carry; p2 = p2.next; } else { sum = p1.val+carry; p1 = p1.next; } } if(sum>=10) { sum = sum-10; carry = 1; } else { carry = 0; } ListNode p = new ListNode(sum); r.next = p; r = p; } if(carry==1) { ListNode p = new ListNode(1); r.next = p; r = p; } return h.next; } }
标签:
原文地址:http://www.cnblogs.com/mrpod2g/p/4311538.html