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读程序,写出函数的定义,注意其中枚举类型的用法。
enum SymmetricStyle {axisx,axisy,point};//分别表示按x轴, y轴, 原点对称 struct Point{ double x; // 横坐标 double y; // 纵坐标 }; double distance1(Point p1, Point p2); // 两点之间的距离,如果用distance,将会与命名空间std中也已经定义的distance函数重名 double distance0(Point p1); Point symmetricAxis(Point p,SymmetricStyle style); //返回对称点 int main( ){ Point p1={1,5},p2={4,1},p; cout<<"两点的距离为:"<<distance1(p1,p2)<<endl; cout<<"p1到原点的距离为:"<<distance0(p1)<<endl; p=symmetricAxis(p1,axisx); cout<<"p1关于x轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl; p=symmetricAxis(p1,axisy); cout<<"p1关于y轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl; p=symmetricAxis(p1,point); cout<<"p1关于原点的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl; return 0; } // 求两点之间的距离 double distance1(Point p1,Point p2) { double d; …… return d; } // 求点到原点的距离 double distance0(Point p) { double d; …… return d; } // 求对称点 Point symmetricAxis(Point p1,SymmetricStyle style) { Point p; …… return p; }
#include <iostream> #include <Cmath> using namespace std; enum SymmetricStyle {axisx,axisy,point};//分别表示按x轴, y轴, 原点对称 struct Point { double x; // 横坐标 double y; // 纵坐标 }; double distance1(Point p1, Point p2); // 两点之间的距离 double distance0(Point p1); Point symmetricAxis(Point p,SymmetricStyle style); //返回对称点 int main( ) { Point p1={1,5},p2={4,1},p; cout<<"两点的距离为:"<<distance1(p1,p2)<<endl; cout<<"p1到原点的距离为:"<<distance0(p1)<<endl; p=symmetricAxis(p1,axisx); cout<<"p1关于x轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl; p=symmetricAxis(p1,axisy); cout<<"p1关于y轴的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl; p=symmetricAxis(p1,point); cout<<"p1关于原点的对称点为:"<<"("<<p.x<<", "<<p.y<<")"<<endl; return 0; } // 求两点之间的距离 double distance1(Point p1,Point p2) { double d; d=sqrt((p1.x-p2.x)*(p1.x-p2.x)+(p1.y-p2.y)*(p1.y-p2.y)); return d; } // 求点到原点的距离 double distance0(Point p) { double d; d=sqrt(p.x*p.x+p.y*p.y); return d; } // 求对称点 Point symmetricAxis(Point p1,SymmetricStyle style) { Point p; p.x=p1.x; p.y=p1.y; switch(style) { case axisx: p.y=-p1.y; break; case axisy: p.x=-p1.x; break; case point: p.x=-p1.x;p.y=-p1.y; } return p; }运行结果:
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原文地址:http://blog.csdn.net/mayuko2012/article/details/44085269