LeetCode Wildcard Matching

标签：

Implement wildcard pattern matching with support for ‘?‘ and ‘*‘.

‘?‘ Matches any single character.
‘*‘ Matches any sequence of characters (including the empty sequence).

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "*") → true
isMatch("aa", "a*") → true
isMatch("ab", "?*") → true
isMatch("aab", "c*a*b") → false

思路：贪心去做，重点是如果匹配"*"，我们需要记录他的位置为start，和此时s串的位置tmp，然后对于p的下一位，我们是希望它能够匹配的，但是如果无法匹配的话，那么此时就需要用到我们标记的"*"的位置了，让"*"去多匹配一个字符，直到“*”的下一位能都匹配成功。

class Solution {
public:
    bool isMatch(const char *s, const char *p) {
        const char *start = NULL, *tmp = NULL;
        while (*s != '\0') {
            if (*s == *p || *p == '?') {
                s++, p++;
                continue;
            }
            if (*p == '*') {
                start = p;
                p++;
                tmp = s;
                continue;
            }
            if (start != NULL) {
                p = start + 1;
                s = tmp + 1;
                tmp++;
                continue;
            }
            return false;
        }      
        while (*p == '*') p++;
        return *p == '\0';
    }
};

LeetCode Wildcard Matching

标签：

原文地址：http://blog.csdn.net/u011345136/article/details/44096509