LeetCode Search Insert Position

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1.题目

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

2.解决方案

class Solution {
public:
    int searchInsert(int A[], int n, int target) {
        for(int i = 0; i < n; i++){
            if(A[i] == target){
                return i;
            }else if((i + 1) < n && A[i] < target && A[i+1] > target){
                return i + 1;
            }
            if(i == n - 1 && A[i] < target){
                return n;
            }
            if(A[0] > target){
                return 0;
            }
        }
        
        return 0;
    }
};

LeetCode Search Insert Position

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原文地址：http://blog.csdn.net/fox64194167/article/details/44101315