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【HDOJ】【3506】Monkey Party

时间:2015-03-06 20:29:09      阅读:143      评论:0      收藏:0      [点我收藏+]

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DP/四边形不等式


  裸题环形石子合并……

  拆环为链即可

技术分享
 1 //HDOJ 3506
 2 #include<cmath>
 3 #include<vector>
 4 #include<cstdio>
 5 #include<cstring>
 6 #include<cstdlib>
 7 #include<iostream>
 8 #include<algorithm>
 9 #define rep(i,n) for(int i=0;i<n;++i)
10 #define F(i,j,n) for(int i=j;i<=n;++i)
11 #define D(i,j,n) for(int i=j;i>=n;--i)
12 #define pb push_back
13 #define CC(a,b) memset(a,b,sizeof(a))
14 using namespace std;
15 int getint(){
16     int v=0,sign=1; char ch=getchar();
17     while(!isdigit(ch)) {if(ch==-) sign=-1; ch=getchar();}
18     while(isdigit(ch))  {v=v*10+ch-0; ch=getchar();}
19     return v*sign;
20 }
21 const int N=2010;
22 const int INF=1000000000;
23 const double eps=1e-8;
24 /*******************template********************/
25 int s[N][N],a[N];
26 int dp[N][N];
27 int main(){
28 #ifndef ONLINE_JUDGE
29     freopen("input.txt","r",stdin);
30 //    freopen("output.txt","w",stdout);
31 #endif
32     int n;
33     while(scanf("%d",&n)!=EOF && n){
34         CC(a,0);CC(s,0);
35         F(i,1,n) a[i+n]=a[i]=getint();
36         F(i,1,n<<1) a[i]+=a[i-1];
37         F(i,1,n*2-1){
38             dp[i][i+1]=a[i+1]-a[i-1];
39             s[i][i+1]=i;
40         }
41         F(len,3,n)
42             F(i,1,n*2-len+1){
43                 int j=i+len-1;
44                 dp[i][j]=INF;
45                 F(k,s[i][j-1],s[i+1][j]){
46                     int tmp=dp[i][k]+dp[k+1][j]+a[j]-a[i-1];
47                     if (tmp<dp[i][j]){
48                         dp[i][j]=tmp;
49                         s[i][j]=k;
50                     }
51                 }
52             }
53         int ans=INF;
54         F(i,1,n) ans=min(ans,dp[i][i+n-1]);
55         printf("%d\n",ans);
56     }        
57     return 0;
58 }
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【HDOJ】【3506】Monkey Party

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原文地址:http://www.cnblogs.com/Tunix/p/4319001.html

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