标签:des c style class blog code
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 ->
4)
Output: 7 -> 0 -> 8
题解: (1)注意处理进位问题。 (2) 注意两个链表长度不相等的时候。
1 class Solution { 2 public: 3 ListNode *add(ListNode *l1, ListNode *l2,int c) 4 { 5 ListNode *head= new ListNode(0); 6 if(l1==NULL && l2==NULL) 7 { 8 if(c==0) 9 return NULL; 10 else 11 { 12 head->val=1; 13 return head; 14 } 15 } 16 if(l1==NULL) 17 return add(head,l2,c); 18 if(l2==NULL) 19 return add(l1,head,c); 20 21 if(l1!=NULL && l2!=NULL) 22 { 23 head->val =(l1->val + l2->val +c)%10; 24 c = (l1->val + l2->val +c)/10; 25 head->next = add(l1->next,l2->next,c); 26 } 27 return head; 28 } 29 ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { 30 int c=0; 31 if(l1==NULL) return l2; 32 if(l2==NULL) return l1; 33 34 ListNode *head = add(l1,l2,c); 35 return head; 36 } 37 };
转载请注明出处: http://www.cnblogs.com/double-win/ 谢谢
LeetCode: Add Two Numbers 题解,布布扣,bubuko.com
标签:des c style class blog code
原文地址:http://www.cnblogs.com/double-win/p/3763401.html