标签:
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
class MinStack {
Stack<Integer> seqStack = new Stack<Integer>();
Stack<Integer> minStack = new Stack<Integer>();
public void push(int x) {
int curMin;
if(minStack.isEmpty()){
curMin = Integer.MAX_VALUE;
} else{
curMin = minStack.peek();
}
if(x <= curMin) minStack.push(x);
seqStack.push(x);
}
public void pop() {
if(seqStack.isEmpty()) return;
else {
int removedValue = seqStack.pop();
if(removedValue == minStack.peek()){
minStack.pop();
}
}
}
public int top() {
return seqStack.peek();
}
public int getMin() {
return minStack.peek();
}
}
标签:
原文地址:http://blog.csdn.net/yangliuy/article/details/44152799