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LeetCode | #27 Remove Element

时间:2015-03-09 17:38:36      阅读:114      评论:0      收藏:0      [点我收藏+]

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题目:

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.

思路:

  • 题目说的是不管新长度之后的内容,即前面留下的是无指定值的数
public class Solution {
    public int removeElement(int[] A, int elem) {
        int size = A.length, index = 0;
        for(int i=0; i<size; i++){
            if(A[i] != elem){
                A[index++] = A[i];
            }
        }
        return index;
    }
}


LeetCode | #27 Remove Element

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原文地址:http://blog.csdn.net/allhaillouis/article/details/44156535

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