高精度之加法

给出两个正整数A和B，计算A+B的值。保证A和B的位数不超过500位。

读入两个用空格隔开的正整数

输出A+B的值

3 12

15

两个正整数的位数不超过500位

思路简单

#include<stdio.h>
#include<string.h>
int main(){
	char a[505], b[505],c[505],d[505];
	int sum[505];
	memset(sum, 0, sizeof(sum));
	/*gets_s(c);
	gets_s(d);*/
	scanf("%s%s", c, d);
	int i, j, tmp, t = 0;
	for (i = strlen(c) - 1, j = 0; i >= 0; i--, j++)
		a[j] = c[i];
	a[j] = '\0';
	for (i = strlen(d) - 1, j = 0; i >= 0; i--, j++)
		b[j] = d[i];
	b[j] = '\0';
	for (i = 0; a[i] != '\0'&&b[i] != '\0'; i++){
		tmp = a[i] - '0' + b[i] - '0' + t;
		t = tmp / 10;
		sum[i] = tmp % 10;
	}
	while (a[i] != 0){
		tmp = a[i] - '0' + t;
		t = tmp / 10;
		sum[i++] = tmp % 10;
	}
	while (b[i] != 0){
		tmp = b[i] - '0' + t;
		t = tmp / 10;
		sum[i++] = tmp % 10;
	}
	for (i = 501; sum[i] == 0; i--);

	while (i >= 0)
		printf("%d", sum[i--]);
	puts("");
	return 0;
}