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LeetCode: Validate Binary Search Tree [098]

时间:2014-06-02 10:29:55      阅读:257      评论:0      收藏:0      [点我收藏+]

标签:leetcode   算法   面试   

【题目】

Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.



【题意】

    给定一棵二叉树,判断是不是合法的二叉搜索树


【思路】

    根据二叉搜索树定义,递归判断即可


【代码】

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    
    bool isValid(TreeNode*root, int lowBound, int upBound){
        //每棵树取值都有上边界和下边界
        if(root==NULL)return true;
        //判断节点值是否在合法的取值区间内
        if(!(root->val>lowBound && root->val<upBound))return false;
        
        //判断左子树是否合法
        if(root->left){
            if(root->left->val >= root->val || !isValid(root->left, lowBound, root->val))return false;
        }
        //判断右子树
        if(root->right){
            if(root->right->val <= root->val || !isValid(root->right, root->val, upBound))return false;
        }
        
        return true;
    }

    bool isValidBST(TreeNode *root) {
        return isValid(root, INT_MIN, INT_MAX);
    }
};


LeetCode: Validate Binary Search Tree [098],布布扣,bubuko.com

LeetCode: Validate Binary Search Tree [098]

标签:leetcode   算法   面试   

原文地址:http://blog.csdn.net/harryhuang1990/article/details/28092249

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