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1 题目
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.
Array Two Pointers
public int removeElement(int[] A, int elem) { int startPosition = 0; for (int i = 0; i < A.length; i++) { if (A[i] != elem) { A[startPosition++] = A[i]; } } return startPosition; }
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原文地址：http://www.cnblogs.com/lingtingvfengsheng/p/4328663.html
