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#include<stdio.h>
int main()
{
int i,n,a[10000],sum,j;
while(~scanf("%d",&n)&&n)
{
sum=1;
for(i=0;;i++)
{
a[i]=n%2;
n=n/2;
if(a[i])
break;
}
for(j=1;j<=i;j++)
sum=sum*2;
printf("%d\n",sum);
}
return 0;
}
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原文地址:http://blog.csdn.net/lihaogegehuting/article/details/44204713