Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times.

You may assume that the array is non-empty and the majority element always exist in the array.

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

代码

import java.util.Hashtable;
import java.util.Iterator;
public class Solution {
    public int majorityElement(int[] num) {
          Hashtable<Integer,Integer> rightList = new Hashtable<Integer,Integer>();
		   for(int i=0;i<num.length;i++)
		      {
			  if(rightList.get(num[i])==null){
				  rightList.put(num[i], 1);
			  }
			  else{
				  rightList.put(num[i], rightList.get(num[i])+1);
			  }
		     }
		   int result_value=0;
		   int result_key=0;
		   for(Iterator itr = rightList.keySet().iterator(); itr.hasNext();){
			  		   int key = (Integer) itr.next(); 
			  		   if(rightList.get(key)>result_value){
			  			  result_key=key;
			  			  result_value=rightList.get(key);			  			   
			  		   }
		   }
		   return result_key;
    }
}