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Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times.
You may assume that the array is non-empty and the majority element always exist in the array.
class Solution {
public:
int majorityElement(vector<int> &num) {
if(num.size() == 1){
return num[0];
}
map<int, int> myMap;
float majorPercent = num.size() / 2.0;
for(int i = 0; i < num.size(); ++i){
int key = num[i];
if(myMap.find(key) == myMap.end()){
myMap.insert(pair<int,int>(key,1));
}else{
int beforeCount = myMap[key];
++beforeCount;
myMap[key] = beforeCount;
if(beforeCount > majorPercent){
return key;
}
}
}
return 0;
}
};http://www.waitingfy.com/archives/1628
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原文地址:http://blog.csdn.net/fox64194167/article/details/44226927