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Two Sum

时间:2015-03-13 18:48:27      阅读:167      评论:0      收藏:0      [点我收藏+]

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Two Sum

 Total Accepted: 70583 Total Submissions: 390661

Given an array of integers, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2


Submission Result: Time Limit Exceeded

Last executed input: [0,2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,100,102,104,106,108,110,112,114,116,118,120,122,124,126,128,130,132,134,136,138,140,142,144,146,148,150,152,154,156,158,160,162,164,166,168,170,172,174,176,178,180,182,184,186,188,190,192,194,196,198,200,202,204,206,208,210,212,214,216,218,220,222,224,226,228,230,232,234,236,238,240,242,244,246,248,250,252,254,256,258,260,262,264,266,268,270,272,274,276,278,280,282,284,286,288,290,292,294,296,298,300,302,304,306,308,310,312,314,316,318,320,322,324,326,328,330,332,334,336,338,340,342,344,346,348,350,352,354,356,358,360,362,364,366,368,370,372,374,376,378,380,382,384,386,388,390,392,394,396,398,400,402,404,406,408,410,412,414,416,418,420,422,424,426,428,430,432,434,436,438,440,442,444,446,448,450,452,454,456,458,460,462,464,466,468,470,472,474,476,478,480,482,484,486,488,490,492,494,496,498,500,502,504,506,508,510,512,514,516,518,520,522,524,526,528,530,532,534,536,538,540,542,544,546,548,550,552,554,556,558,560,562,564,566,568,570,572,574,576,578,580...10200

int Index[2] = {0,0};

int*
twoSum(int numbers[], int n, int target)
{
    int i,j;
    int Index1,Index2;
    for( i = 0; i < n; i++ )
    {
        for( j = i+1; j < n; j++ )
            if( numbers[i] + numbers[j] == target )
            {
                Index1 = i;
                Index2 = j;
            }
    }

    Index[0] = Index1 + 1;
    Index[1] = Index2 + 1;

    return Index;
}

Two Sum

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原文地址:http://blog.csdn.net/oimchuan/article/details/44244011

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