蓝桥杯 BASIC-10~12 进制转化

标签：acm   蓝桥杯   

十进制转十六进制

【AC代码】：更简单采用直接输出的方式。

#include <iostream>
#include <algorithm>
#include <cstdio>
using namespace std;

int main()
{
	//freopen("in.txt", "r", stdin);
	//freopen("out.txt", "w", stdout);
	int n = 0, cnt = 0, i = 0;
	cin >> n;
	char Hex[20];
	if (0 == n)
		cout << 0;
	while (n)
	{
		int temp = n%16;
		n = n/16;
		switch(temp)
		{
			case 0:
			case 1:
			case 2:
			case 3:
			case 4:
			case 5:
			case 6:
			case 7:
			case 8:
			case 9:
				Hex[cnt++] = temp+'0';
				break;
			case 10:
			case 11:
			case 12:
			case 13:
			case 14:
			case 15:
				Hex[cnt++] = temp-10+'A';
				break;
		}
	}
	for (i = cnt-1; i >= 0; i--)
		cout << Hex[i];
}

十六进制转十进制

【AC代码】：更简单采用直接输出的方式。

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;

int main()
{
	//freopen("in.txt", "r", stdin);
	//freopen("out.txt", "w", stdout);
	char Hex[20];
	gets(Hex);
	int i = 0, len = strlen(Hex);
	long long int sum = 0;
	for (i = len-1; i >= 0; i--)
	{
		if (Hex[i] >= '0' && Hex[i] <= '9')
			sum += (Hex[i]-'0') * pow(16, len-1-i);
		else
			sum += (Hex[i]-'A'+10) * pow(16, len-1-i);
	}
	cout << sum;
}

十六进制转十进制

【AC代码】：因为题目范围限制，所以不能采用直接输出的方式。

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <iomanip>
using namespace std;

#define MAX 100000+10

int toNum(char c)
{
	if (c >= 'A')
		return c - 'A'+10;
	else
		return c - '0';
}

int main()
{
	//freopen("in.txt", "r", stdin);
	//freopen("out.txt", "w", stdout);
	int t = 0;
	cin >> t;
	while (t--)
	{
		char Hex[MAX];
		cin >> Hex;
		int i = 0, len = strlen(Hex);
		if (1 == len%3)
		{
			cout << oct << toNum(Hex[0]);
			i = 1;
		}
		else if (2 == len%3)
		{
			cout << oct << toNum(Hex[0])*16 + toNum(Hex[1]);
			i = 2;
		}
		for ( ; i < len; i+=3)
		{
			cout << setw(4) << setfill('0') << oct << toNum(Hex[i])*256 + toNum(Hex[i+1])*16 + toNum(Hex[i+2]);
		}
		cout << endl;
	}
}

蓝桥杯 BASIC-10~12 进制转化

标签：acm   蓝桥杯   

原文地址：http://blog.csdn.net/weijj6608/article/details/44246435