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分析:
很简单,就是输出0~32 的二进制形式
32中可能 就是最多5位数
00000
00001
00010........
输出即可
#include <iostream>
#include "stdio.h"
#include "stdlib.h"
using namespace std;
int main(int argc, char *argv[])
{
int a[5];
int num = 0;
for (int i = 0; i < 5; i++)
{
a[i] = 0;
}
int ge, ss, b, s, q;
for (int i = 0; i < 32; i++)//循环32次 0~32
{
//10进制转换为2进制
num = i;
q = num / 2;
a[4] = num % 2;
s = q / 2;
a[3] = q % 2;
b = s / 2;
a[2] = s % 2;
ss = b / 2;
a[1] = b % 2;
ge = ss / 2;
a[0] = ss % 2;
//输出该二进制
for (int i = 0; i < 5; i++)
{
cout << a[i];
}
cout << endl;
}
return 0;
}
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原文地址:http://my.oschina.net/u/1391394/blog/387070